Question

A formula for the normal systolic blood pressure for a man age A, measured in mmHg, is given as
P=0.006 A2 -0.02A + 120. Find the age to the nearest year of a man whose normal blood pressure measures 125
mmHg.

Answer 1

Answer:

211 years

Step-by-step explanation:

A formula for the normal systolic blood pressure for a man age A, measured in mmHg, is given as

$P=0.006 A^2 -0.02A + 120$ ....(1)

We need to find the age to the nearest year of a man whose normal blood pressure measures 125  mmHg.

Put A = 125 mmHg in the given equation.

$P=0.006 (125)^2 -0.02(125) + 120\\\\=211.25$

So, the nearest age of a man is 211 years.

Answer 2

The age to the nearest year of a man whose normal blood pressure measures 125  mmHg is; A = 31 years

• We are given the formula for the normal systolic blood pressure for a man as;

P = 0.006A² - 0.02A + 120

Where;

P is normal systolic blood pressure

A is age of the man

• Thus, if the normal systolic blood pressure of the man is 125 mmHg, then;

125 = 0.006A² - 0.02A + 120

Using subtraction property of equality gives;

125 - 125 = 0.006A² - 0.02A + 120 - 125

0 = 0.006A² - 0.02A - 5

Using online quadratic equation solver gives;

A = 30.5823 or -27.2489

Age cannot be negative and so we take the positive one as;

A = 30.5823

Approximation to the nearest year gives;

A = 31 years

Read more at; https://brainly.com/question/14193054