find the values of x and y
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Answer:
x = 90
y = 43
Step-by-step explanation:
[tex] In\: \triangle ABC\\
AB = AC.... (given)
\therefore m\angle ABC = m\angle ACB\\[/tex] (Property of isosceles triangle)
[tex] \because m\angle ACB = 47\degree \\
\therefore m\angle ABC = 47\degree \\
2y\degree + 47\degree+47\degree = 180\degree \\
2y\degree + 94\degree= 180\degree \\
2y\degree = 180\degree - 94\degree \\
2y\degree = 86\degree \\\\
y = \frac{86\degree}{2} \\\\
y\degree = 43\degree \\\\
\huge \purple {\boxed {y = 43}} \\\\[/tex]
x° + y° + 47°=180°
x° + 43° + 47°=180°
x ° + 90° = 180°
x ° = 180° - 90°
x° = 90°
x = 90