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In the diagram below,AB is the diameter of the circle with centre P.Point C lies on the y-axis.Given the coordinates of A and B are (-6,3) and (2,-3) respectively ,calculate

a)the coordinates of P





b)radius of the circle





c)the coordinates of C





d)the area of the circle in term of
[tex]\pi[/tex]

In the diagram belowAB is the diameter of the circle with centre PPoint C lies on the yaxisGiven the coordinates of A and B are 63 and 23 respectively calculate class=

Respuesta :

Answer:

The coordinates of P are (-2,0)

The radius of the circle is 5.

Step-by-step explanation:

Analytic geometry

The diagram shows a circle with center P, and two points A(-6,3) and B(2,-3) that form the diameter of the circle.

a)

The center of the circle lies at the midpoint of A and B. The midpoint (xm,ym) can be calculated by:

[tex]\displaystyle x_m=\frac{x_1+x_2}{2}[/tex]

[tex]\displaystyle y_m=\frac{y_1+y_2}{2}[/tex]

Substituting x1=-6, x2=2, y1=3, y2=-3:

[tex]\displaystyle x_m=\frac{-6+2}{2}=\frac{-4}{2}=-2[/tex]

[tex]\displaystyle y_m=\frac{3-3}{2}=0[/tex]

Thus, the coordinates of P are (-2,0)

b) The radius of the circle is the distance from the center to any point in its circumference. We can use the distance from P to A or B indistinctly.

Given two points A(x1,y1) and P(x2,y2), the distance between them is:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Substituting x1=-6, x2=-2, y1=3, y2=0:

[tex]r=\sqrt{(-2+6)^2+(0-3)^2}[/tex]

[tex]r=\sqrt{4^2+(-3)^2}[/tex]

[tex]r=\sqrt{16+9}=\sqrt{25}=5[/tex]

The radius of the circle is 5.

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