Question

24. Michael leaves his house at 0837 and travels by motorcycle to the railway station, which is 27 km from his
house.
(i) If he arrives at the station 36 minutes later, find the average speed at which he travels in km/h.
(ii) If the train, which is due at 0942, is 11 minutes late, how long will he have to wait?

Answer 1

Answer:

i) 45km/hr

ii)29 min

Step-by-step explanation:

average speed = distanced travelled / time elapsed

It took 36min and need to convert to hr

36min x $\frac{hours}{60 min}$ = $\frac{36 hr}{60 min}$ = $\frac{9 }{15 }$ hours

distanced travelled is 27 km;

average speed = 27km / (9/15hr) = 45 km/hr

Add 36min to 0837 becomes 0913, the train will arrive at 0942 and the wait will be the difference of 0942 - 0913 = 29 min