Question

what is the point slope equation of the line through (3,6) (5,-8)

Answer 1

Answer:

y-6 = -7(x-3)

Step-by-step explanation:

$y-y_{1} =m(x-x_{1})$

y - 6 = m(x - 3)

$m = \frac{-8-6}{5-3}=\frac{-14}{2}=-7$

y-6 = -7(x-3)

Answer 2

Answer:

y - 6 = -7(x - 3)

General Formulas and Concepts:

Pre-Algebra

• Order of Operations: BPEMDAS

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Point-Slope Form: y - y₁ = m(x - x₁)  

• x₁ - x coordinate

• y₁ - y coordinate

• m - slope

Step-by-step explanation:

Step 1: Define

Point (3, 6)

Point (5, -8)

Step 2: Find slope m

1. Substitute:                    $m=\frac{-8-6}{5-3}$
2. Subtract:                       $m=\frac{-14}{2}$
3. Divide:                          $m=-7$

Step 3: Write equation

Point (3, 6)

Slope m = -7

y - 6 = -7(x - 3)