Given:
The value is [tex]\log_7t[/tex].
To find:
The value as a base 2 logarithm.
Solution:
We know that,
[tex]\log_xy=\dfrac{\log_ay}{\log_ax}[/tex]
where, a is any positive value.
We have,
[tex]\log_7t[/tex]
Using the above property of logarithm, we get
[tex]\log_7t=\dfrac{\log_at}{\log_a7}[/tex]
For a=2,
[tex]\log_7t=\dfrac{\log_2t}{\log_27}[/tex]
Therefore, the given value as a base 2 logarithm can be written as [tex]\dfrac{\log_2t}{\log_27}[/tex].
Answer:
log2t/log2^7
Step-by-step explanation:
(what the other dude said)
