Question

X^2+16y^2 = 16 list the intercepts and check for symmetry

Answer 1

Hello,

$( \dfrac{x}{4} )^2+ y^2=1\\ x=0==\ \textgreater \ y=1\ or\ y=-1\\ y=0==\ \textgreater \ x=4\ or\ x=-4$
This is the equation of an ellipse with center=(0,0);
Symmetry' axis are y=0 and x=0.