Question

A number n is more than 9 units from 3. The absolute value inequality is?

Answer 1

Answer:

$|n-3|>9$

Step-by-step explanation:

A number n is more than 9 units from 3.

We use number line. find out the number that is 9 units from 3 on the right of 3 and left of 3

3+9 = 12

3 -9 = -6

So 12 and -6 are 9 units from 3

number 'n' is more than 9 units

x <-6 or x>12

we can also write

x-3 <-9 or x-3>9

In general, if x<-a or x>a  then absolute inequality is

|x|>a

x-3 <-9 or x-3>9

Absolute value inequality becomes

$|n-3|>9$

Answer 2

The absolute value inequality is $|n-3|>9$.

Given that,

• There is the number n i.e. more than 9 units from 3.

Based on the above information, the calculation is as follows:

• Here we use the number line.

3+9 = 12

3 -9 = -6

Therefore 12 and -6 should be 9 units from 3.

Also,  n should be more than 9 units.  

It can be like

x <-6 or x>12

or  

x-3 <-9 or x-3>9

Therefore we conclude that The absolute value inequality is $|n-3|>9$.

Learn more: brainly.com/question/17429689