Respuesta :
Here is the solution of the given problem above.
Given: Weight of single calf = weight of mother + 3.8%
Weight of mother = 3.75 tons or 7,500 pounds
? = weight of the calf
First, we need to find the 3.8% of 7,500 pounds. The result is 285 pounds.
So to get the weight of the calf, let's add 7,500 pounds to 285 pounds and the result is 7,785 pounds. So the weight of the calf is 7,785 pounds. Hope this helps.
Given: Weight of single calf = weight of mother + 3.8%
Weight of mother = 3.75 tons or 7,500 pounds
? = weight of the calf
First, we need to find the 3.8% of 7,500 pounds. The result is 285 pounds.
So to get the weight of the calf, let's add 7,500 pounds to 285 pounds and the result is 7,785 pounds. So the weight of the calf is 7,785 pounds. Hope this helps.
Answer: [tex]285\text{ pounds}[/tex]
Step-by-step explanation:
Given :The average white rhinoceros gives birth to a single calf that weighs about 3.8% as much as its mother.
We can convert percent into decimal by dividing it by 100.
Thus , 3.8% will become 0.038.
If the mother rhinoceros weighs 3.75 tons, then the number of pounds its calf weigh is given by :-
[tex]0.038\times3.75=0.1425\text{ tons}[/tex]
We know that 1 ton = 2000 pounds
Then, Weight of calf = [tex]0.1425\times2000=285\text{ pounds}[/tex]
Hence, the required answer is [tex]285\text{ pounds}[/tex] .