Respuesta :
General equation of the line
y = mx + c
m=1/2
so
y = (1/2)x + c
if it passes through origin (0,0)
0 = (1/2*0) + c
0 = 0 + c
c = 0
so the equation is
y = (1/2)x
if the x is equal to 2,
y is (1/2)*2 = 1
so the point will be
(2,1)
y = mx + c
m=1/2
so
y = (1/2)x + c
if it passes through origin (0,0)
0 = (1/2*0) + c
0 = 0 + c
c = 0
so the equation is
y = (1/2)x
if the x is equal to 2,
y is (1/2)*2 = 1
so the point will be
(2,1)
Answer:
#1 Passing point: (2,1)
#2 Slope = 3
Step-by-step explanation:
#1
A line passes through the origin and has a slope of 1/2
Passing point (0,0) and Slope (m) = 1/2
Using Point Slope form:
[tex]y-y_1=m(x-x_1)[/tex]
[tex]y-0=\dfrac{1}{2}(x-0)[/tex]
[tex]y=\dfrac{1}{2}x[/tex]
Check Point: (2,1)
[tex]1=\dfrac{1}{2}\times 2\Rightarrow 1=1[/tex] TRUE
Hence, The passing point is (2,1)
#2
The slope of the line passing through (1, 2) and (3,8)
Formula:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\dfrac{8-2}{3-1}[/tex]
[tex]m=3[/tex]
Hence, The slope of line passing through two points is 3