Question

Please hurry I'm in a test!!!
Consider the following intermediate chemical equations.

2 equations. First: 2 upper N a (s) plus upper C l subscript 2 (g) right arrow 2 upper N a upper C l (s). Second: 2 upper N a subscript 2 upper O (s) right arrow 4 upper N a (s) plus upper O subscript 2 (g).

In the final chemical equation, NaCl and O subscript 2 are the products that are formed through the reaction between Na subscript 2 O and Cl subscript 2. Before you can add these intermediate chemical equations, you need to alter them by
A.) multiplying the second equation by 2.
B.) multiplying the first equation by 2.
C.) multiplying the first equation by (1/2).
D.) multiplying the second equation by (1/4).

Answer 1

Answer:

OMG Why has nobody answered this FREE 40 POINTS!!!!

For your ConVenIence Sir!

I shall provide thine with the answer, copied from other great sir.

B.) multiplying the first equation by 2.

Explanation:

Here is an image for Thine HappyNess!!!!!!!!!!!!! :D :D :D :D

Answer 2

Before adding the intermediate chemical equations to get the final products first we have to multiplying the first equation by 2.

What is the stoichiometry?

Stoiciometry of any chemical reaction gives idea about the amount of species present before and after the completion of the reaction.

Given first intermediate chemical equation is:

2Na(s) + Cl₂ → 2NaCl(s)

Second intermediate chemical equation is:

2Na₂O(s) → 4Na(s) + O₂(g)

Final products of the given chemical reactions are NaCl and O₂ which are formed by the below given balanced chemical reaction:

2Na₂O + Cl₂ → 4NaCl + O₂

To get the desire balance chemical equation before adding the given intermediate equation, first we have to multiply the first equation by 2.

Hence option (B) is correct.

To know more about stoichiometry, visit the below link:
https://brainly.com/question/16060199