Calculate the net acceleration acting on a 40 kg box being pushed across a horizontal floor. There is a 400 N normal force, a 195 N applied force, and a 55 N force of friction resisting any sliding motion. Assume g = 10 m/s ^ 2

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Lanuel

Answer:

Net acceleration = 3.5m/s²

Explanation:

Given the following data;

Mass, m = 40kg

Normal force, Fn = 400N

Applied force, Fapp = 195N

Force of friction, Ff = 55N

Mathematically, the net force is given by the formula;

[tex] F_{net} = F_{app} - F_{f}[/tex]

Substituting into the equation, we have;

[tex] F_{net} = 195 - 55 [/tex]

[tex] F_{net} = 140 [/tex]

To find the acceleration;

[tex] F_{net} = ma[/tex]

Making acceleration "a" the subject of formula;

[tex]a = \frac {F_{net}}{m} [/tex]

[tex]a = \frac {140}{40} [/tex]

Net acceleration, a = 3.5m/s²