Question

David Ortiz has 489 at bats with 155 hits. He had 47 doubles, 1 triple, and 34 Home runs. How many singles did Ortiz have? What was his slugging average?

Answer 1

Answer: Ortiz had 73 singles.

His slugging average =0.6503

Step-by-step explanation:

Given: At bats = 489

Total hits = 155

Doubles = 47

triple =1

Home runs = 34

Number of singles = (Total hits )-(Doubles +triple + Home runs)

= 155-(47+1+34)

= 155 - 82 =73

So, Ortiz had 73 singles.

Total Bases = 3(Triples)+ 1(singles) + 2 (doubles)+ 4 (Home runs)

= 3(1)+1(73)+2(47)+4(37)

= 3+73+ 94+148 =318

At bats = 489

$\text{Slugging average}=\dfrac{\text{Total bases}}{\text{At bats}}\\\\=\dfrac{318}{489}=0.6503$

Hence, his slugging average =0.6503