Answer:
[tex]Bronze = \frac{1}{4}[/tex]
Step-by-step explanation:
Given
[tex]Gold = \frac{5}{12}[/tex]
[tex]Silver = \frac{1}{3}[/tex]
Required
Determine the probability of Bronze medal
In probability, sum is always equal to 1
i.e.
[tex]Gold + Silver + Bronze = 1[/tex]
Make Bronze the subject
[tex]Bronze = 1 - Gold - Silver[/tex]
Substitute values for Gold and Silver
[tex]Bronze = 1 - \frac{5}{12} - \frac{1}{3}[/tex]
Take LCM
[tex]Bronze = \frac{12 - 5 - 4}{12}[/tex]
[tex]Bronze = \frac{3}{12}[/tex]
[tex]Bronze = \frac{1}{4}[/tex]
Hence:
The probability of picking bronze is
[tex]Bronze = \frac{1}{4}[/tex]