Question

A bag contains 10 white, 12 blue, 13 red, 7 yellow, and 8 green wooded balls. A ball is selected from the bag and kept. You then draw a second ball and keep it also. What is the probability of selecting one white ball and one blue ball

Answer 1

Answer:

0.096

Step-by-step explanation:

The bag contains 10 white , 12 blue, 13 red , 7 yellow and 8 green balls.

All the events of drawing a ball will be independent

so selecting one ball white and one red will be

using the multiplication rule of probability we get

P= P(blue)* P(white) + P(white)*P(blue)

as its said to get one blue and one white but does not specify to get which ball at which place  

P= $\frac{12}{50}*\frac{10}{50} + \frac{10}{50}*\frac{12}{50}$

P= $\frac{240}{2500}$ = 0.096