A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence interval for the population mean. Round your answers to one decimal place. ( , ) b. Assume that the same sample mean was obtained from a sample of items. Provide a confidence interval for the population mean. Round your answers to two decimal places. ( , ) c. What is the effect of a larger sample size on the interval estimate

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Step-by-step explanation:

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In point a:

[tex]a=0.05 \\\\| Z(0.025)|= 1.96 \text{(check in normal table)} \\\\ 95 \% \ CI \\\\\bar x \pm \ Z \times \frac{s}{\sqrt{n}}\\\\\to 80 \pm 1.96 \times \frac{15}{\sqrt{60}} \\\\\to (76.20448, 83.79552)[/tex]

In point b:

[tex]95 \% \ CI \ is \\\\ \bar x \pm Z \times \frac{s}{\sqrt{n}}\\\\\to 80 \pm 1.96 \times \frac {15}{\sqrt{120}}\\\\\to (77.31616, 82.68384)[/tex]

In point c:

A large sample is a smaller error margin.

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