Answer:
The water speed in this narrowed portion of the stream is 2.7 m/s.
Explanation:
Given;
initial speed of the stream, v₁ = 0.9 m/s
let the initial area of the stream, = A₁
then, the final area of the stream, A₂ = ¹/₃A₁
final speed of the water, v₂ = ?
Apply continuity equation;
A₁v₁ = A₂v₂
[tex]v_2 = \frac{A_1v_1}{A_2}\\\\v_2 = \frac{A_1(0.9)}{A_1/3}\\\\v_2 = \frac{3A_1(0.9)}{A_1}\\\\v_2 = 3(0.9)\\\\v_2 = 2.7 \ m/s[/tex]
Therefore, the water speed in this narrowed portion of the stream is 2.7 m/s.