Answer:
CuSO4.5H2O
Explanation:
Recall that;
mass of anhydrous salt/ molar mass of anhydrous salt = mass of hydrated salt/molar mass of hydrated salt
mass of anhydrous salt = 27.38 g
mass of hydrated salt = 42.75 g
molar mass of anhydrous salt = 160 g/mol
molar mass of hydrated salt = 160 + 18x
27.38 g/160 g/mol = 42.75 g/160 + 18x
27.38 (160 + 18x) =160 * 42.75
4380.8 + 492.84x = 6840
492.84x = 6840 - 4380.8
492.84x = 2459.2
x = 2459.2/492.84
x = 5
Hence the formula of the hydrate is; CuSO4.5H2O