Question

MY NOTES ASK YOUR TEACHER In the Bohr model of the hydrogen atom, an electron in the 8th excited state moves at a speed of 3.42 104 m/s in a circular path of radius 3.39 10-9 m. What is the effective current associated with this orbiting electron

Answer 1

Answer:

The value is $I = 2.568*10^{-7}\ A$

Explanation:

From the question we are told that

   The speed of the electron is  $v = 3.42*10^{4} \ m/s$

    The radius is  $r = 3.39 *10^{-9} \ m$

Generally the frequency of the electron is mathematically represented as

      $f = \frac{v}{2 \pi * r }$

=>   $f = \frac{3.42 *10^{4}}{2 * 3.142 * 3.39*10^{-9} }$

=>   $f = 1.605 *10^{12} \ s^{-1}$

Generally the current is mathematically represented as

       $I = e * f$

Here e is the charge on an electron with value $e = 1.60*10^{-19} \ C$

So

      $I = 1.60*10^{-19} *1.605 *10^{12}$

=>   $I = 2.568*10^{-7}\ A$