Question

A dart hits a dartboard and stops in 0.060 s. The net force on the dart is 14 N during the collision.
What is the magnitude of the change in momentum of the dart?

Round number to two significant digits

Answer 1

Answer:

The change of momentum of the dart is 0.84 Nw.s

Explanation:

Impulse and change of momentum

The change in momentum of an object is its mass times the change in its velocity:

$\Delta p=m\Delta v=m(v_2-v_1)$

The change in the momentum can also be found by considering the force acting on it. If a force F acts for a time Δt, the change of momentum is given by:

$\Delta p=F.\Delta t$

The dart hits a dashboard with a net force of 14 N during the collision and stops in 0.06 seconds. The change of momentum is:

$\Delta p=14*0.06=0.84$

The change of momentum of the dart is 0.84 Nw.s