Question

A helium laser emits light with a wavelength of 633 nm. What is the frequency, v, of the light?​

Answer 1

Answer:

4.74×10¹⁴ Hz.

Explanation:

From the question given above, the following data were obtained:

Wavelength of light = 633 nm.

Frequency of light =?

Next, we shall convert 633 nm to metre (m)

This can be obtained as follow:

1×10⁹ nm = 1 m

Therefore,

633 nm = 633 nm × 1 m / 1×10⁹ nm

633 nm = 6.33×10¯⁷ m

Thus, 633 nm is equivalent to 6.33×10¯⁷ m

Finally, we shall determine the frequency of the light as follow:

Wavelength of light = 6.33×10¯⁷ m

Velocity of light = 3×10⁸ m/s

Frequency of light =?

Velocity = wavelength x frequency

3×10⁸ = 6.33×10¯⁷ x frequency

Divide both side by 6.33×10¯⁷

Frequency = 3×10⁸ / 6.33×10¯⁷

Frequency = 4.74×10¹⁴ Hz.

Therefore, the frequency of the light is 4.74×10¹⁴ Hz.

Answer 2

The frequency, f, of the light emitted at a wavelength of 633 nm is 4.74 × 10¹⁴ Hz

HOW TO CALCULATE WAVELENGTH:

• The wavelength of a wave can be calculated by dividing the velocity by its frequency. That is;

λ = v/f

Where;

1. λ = wavelength (m)
2. v = velocity (m/s)
3. f = frequency (Hz)

• According to this question, a helium laser emits light with a wavelength of 633 nm i.e. 6.33 × 10-⁷m

• f = 3 × 10⁸ ÷ 6.33 × 10-⁷

• f = 0.474 × 10⁸+⁷

• f = 4.74 × 10¹⁴ Hz

• Therefore, frequency, f, of the light emitted at a wavelength of 633 nm is 4.74 × 10¹⁴ Hz.

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