Question

What are the solutions of 2x2 8x = –26? –2 ± 3i –2 ± i 2 ± 6i –3 ± 2i

Answer 1

Hello,

2x²+8x+26=0
==>x²+4x+13=0
Δ=4²-4*13-36

x=(-4+6i)/2 or x=(-4-6i)/2

x=-2+3i  or x=-2-3i

Answer A

Answer 2

2x^2+8x=-26
divide both sides by 2
x^2+4x=-13
add 13 both sides
x^2+4x+13=0
a=1
b=4
c=13
x=$\frac{-4+/- \sqrt{4^2-4(1)(13)} }{2(1)}$
x=$\frac{-4+/- \sqrt{16-52} }{2}$
x=$\frac{-4+/- \sqrt{-36} }{2}$
x=$\frac{-4+/- (\sqrt{-1})(\sqrt{36}) }{2}$
x=$\frac{-4+/- i\sqrt{36} }{2}$
x=$\frac{-4+/- 6i}{2}$
x=-2+/-3i


solutions are
-2+3i and -2-3i