Question

Factor the perfect-square trinomial in y = (x2 + 2x + 1) − 1− 1.
y = (x +
)2 − 1 −1

Answer 1

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$y = ( {x}^{2} + 2x + 1) - 1$

$y = ({x + 1})^{2} - 1$

$y = ({x + 1})^{2} - ({1})^{2}$

We're done now but I have something to tell...

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Hint :

${a}^{2} - {b}^{2} = (a + b)(a - b)$

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$y = ( \: (x + 1) + 1)( \: (x + 1) - 1)$

$y = (x + 2)(x)$

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Answer 2

Answer:

1

Step-by-step explanation: