Question

Let u =Vector X Y where X(–4, 6) and Y(8, 3). What is Magnitude of 2 u?

6 StartRoot 17 EndRoot
18
3 StartRoot 17 EndRoot
612

I will give brainliest but need answer ASAP

Answer 1

Answer:

A) 6√17

Step-by-step explanation:

got it right on edge :)

Answer 2

As per the distance between two points, the required magnitude of '2u' is 24.74.

What is the distance between two points?

"The distance between two points can be evaluated if we know the coordinates of the two points in the XY plane. If P(x₁, y₁) and Q(x₂, y₂) are the two points in a plane, then the distance between P and Q can be evaluated using the distance formula, such as:

$PQ = \sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}$

The difference between the x-axis coordinates gives the horizontal distance and the difference between the y-axis coordinates gives the vertical distance."

Here, two end points of the given vector 'u' are  X(–4, 6) and Y(8, 3).

Therefore, magnitude of the 'u' vector is

= distance between X and Y

$\sqrt{(8 - (-4))^{2}+(3-6)^{2}}\\= \sqrt{12^{2}+(-3)^{2}}\\= \sqrt{144+9}\\ = \sqrt{153}\\= 12.37$

Here, the distance between two points X and Y is 12.37.

Now, the magnitude of '2u' is

= 2 × 12.37

= 24.74

Learn more about the distance between two points here: https://brainly.com/question/16410393

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