Answer:
a. Total revenue = Number of units sold * price of suit
= x * (140 - 0.5x)
= 140x - 0.5x²
b. Total profit = Revenue - Costs
= 140x - 0.5x² - (2000 + 0.75x²)
= 140x - 2,000 - 1.25x²
c. The profit is maximized at a quantity where the derivative of the profit function equals zero.
Derivative = 140 - 2.5x
Maximized profit ;
140 - 2.5x = 0
2.5x = 140
x = 56 suits
d. Maximum profit using the profit function;
= 140x - 2,000 - 1.25x²
= (140 * 56) - 2,000 - (1.25 * 56²)
= 7,840 - 2,000 - 3,920
= $1,920
e. Price per suit;
= 140 - 0.5x
= 140 - 0.5 * 56
= $112 per suit