Question

a researcher obtains a sample of 0.070 M nitrate solition. A 20.0 mL aliquote of the nitrate solution is added to 10.0 mL of ammonia and diluted to 100 ml with deionized water. what is the concentration of nitrate in the new solution

Answer 1

Answer:

Concentration of nitrate in the new solution = 0.007 M

Explanation:

Given:

Concentration nitrate solution = 0.070 m

Volume of aliquote of the nitrate solution is add = 10.0 ml

Total volume = 100 ml

Find:

Concentration of nitrate in the new solution

Computation:

Number of M. mole = 0.070 m x 10.0 ml

Number of M. mole = 0.7 m-moles

Concentration of nitrate in the new solution = 0.7 m-moles / 100 ml

Concentration of nitrate in the new solution = 0.007 M

Answer 2

The Concentration of nitrate in the new solution is 0.007 M.

Calculation of the concentration;

Since

Concentration nitrate solution = 0.070 m

The Volume of aliquots of the nitrate solution is added = 10.0 ml

And, Total volume = 100 ml

So here the

Number of M. mole = 0.070 m x 10.0 ml

= 0.7 m-moles

Now

Concentration of nitrate in the new solution should be

= 0.7 m-moles / 100 ml

= 0.007 M

hence, The Concentration of nitrate in the new solution is 0.007 M.

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