Question

The 300 students at Holmes School work a total of 5000 hours each month. Each

student in group A works 10 hours, each in group B works 15 hours, and each in

group C works 20 hours each month. There are twice as many students in group B as

in group A. Which equation would not be included in the system used to solve this

problem?

AB=2A

CA + B + C = 300

B 10A + 15B + 200 = 5000 D A = 2B

Answer 1

Answer:

$A = 2B$

Step-by-step explanation:

Given

$Students = 300$

$Hours = 5000$

$Group\ A = 10$

$Group\ B = 15$

$Group\ C = 20$

Required

Which of the options is incorrect?

From the question, we understand that there are 300 students.

This implies that:

$A + B + C = 300$

From the question, we understand that there are 5000 hours.

This implies that:

$10A + 15B + 20C = 5000$

Also, we understand that there are twice as many B as A.

This implies that:

$B = 2A$

So, from the list of given options and the analyses done above.

$A = 2B$

is the odd one among them