Answer: 1050
Step-by-step explanation:
Number of combinations of selecting r things out of n = [tex]^nC_r=\dfrac{n!}{r!(n-r)!}[/tex]
such that [tex]^nC_1=n[/tex]
Given: A restaurant menu has 5 kinds of soups, 7kinds of main courses, 6 kinds of desserts, and 5 kinds of drinks.
If a customer randomly selects one item from each of these four categories, then by fundamental counting principle , the number of different outcomes are possible = [tex]^5C_1\times \ ^7C_1\times\ ^6C_1\times\ ^5C_1 =5\times7\times6\times5=1050[/tex]
hence, total number of outcomes = 1050
