Answer:
Explanation:
Complete question:
An AC power source has an rms voltage of 120 V and operates at a frequency of 60.0 Hz. If a purely inductive circuit is made from the power source and a 43.8H inductor, determine the inductive reactance and the rms current through the inductor.
Inductive reactance XL = 2πfL
f is the frequency
L is the inductance
Given
f = 60Hz
L = 43.8H
XL = 2π(60)(43.8)
XL = 376.8(43.8)
XL = 16,503.84ohms
Irms is the root mean square current
V = IXL
I = V/XL
I = 120/16,503.84
I = 0.00727A
Hence the current through the inductor is I = 0.00727A
