Respuesta :
[tex]A=P(1+ \frac{r}{n})^{nt} [/tex]
A=future amount
P=present amount
r=rate in decimals
n=number of times per year it is compounded
t=time in years
P=50
r=0.05
n=1
t=t
[tex]A=50(1+ \frac{0.05}{1})^{(1)(t)} [/tex]
[tex]A=50(1+0.05)^{t} [/tex]
[tex]A=50(1.05)^{t} [/tex]
the amount of money is [tex] 50(1+0.05)^{t} [/tex] after t years
A=future amount
P=present amount
r=rate in decimals
n=number of times per year it is compounded
t=time in years
P=50
r=0.05
n=1
t=t
[tex]A=50(1+ \frac{0.05}{1})^{(1)(t)} [/tex]
[tex]A=50(1+0.05)^{t} [/tex]
[tex]A=50(1.05)^{t} [/tex]
the amount of money is [tex] 50(1+0.05)^{t} [/tex] after t years