Answer:
The current inside the MRI solenoid is 2387 A.
Explanation:
Given;
number of turns, N = 400
radius of the loop, r = 0.66 m
magnetic field, B = 1.2 T
The magnetic field strength inside MRI Solenoid is given by;
B = Nμ₀I
Where;
I is the current needed in the loop
[tex]B= N\mu_o I\\\\I = \frac{B}{N \mu_o} \\\\I = \frac{1.2}{(400)(4\pi* 10 ^{-7})} \\\\I = 2387 \ A[/tex]
Therefore, the current inside the MRI solenoid is 2387 A.