Answer:
Step-by-step explanation:
Given that: Training-session duration of female rowers with normal iron status is Normally distributed, with mean 69 minutes and standard deviation 18minutes.
Solution:
z score shows the relationship between sample means. The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by the formula:
[tex]z=\frac{x-\mu}{\sigma}\\\\for\ sample(n):\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} } \\\\where\ \mu=mean,\sigma=standard\ deviation,x=raw\ score[/tex]
Given that μ = 69 minutes, σ = 18 minutes, n = 24
For x > 63 minutes:
[tex]z=\frac{x-\mu}{\sigma / \sqrt{n} } =\frac{63-69}{18/\sqrt{24} }=-1.63[/tex]
From the distribution table, P(x > 63) = P(z > -1.63) = 1 - P(z < 1.63) = 1 - 0.0516 = 0.9484
