Answer:
Specific heat capacity = 0.173 j/g.°C
Explanation:
Given data:
Mass of sample = 54.07 g
Heat required = 170.97 j
Initial temperature = 15.2 °C
Final temperature = 33.5°C
Specific heat capacity = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 33.5°C - 15.2°C
ΔT = 18.3°C
170.97 j = 54.07 g × c × 18.3°C
170.97 j = 989.48 g.°C × c
c = 170.97 j /989.48 g.°C
c = 0.173 j/g.°C
