Question

A horizontal 2.0 x 101 N forces pushes an object along a level surface at a constant speed of 3.0m/s for 7.0 s. How much work is done?
a. 21 J b. 60 J c. 140 J d. 420 J

Answer 1

Answer:

420J

Explanation:

Given parameters:

Force  = 2 x 10¹N

Speed  = 3m/s

Time  = 7s

Unknown:

Work done  = ?

Solution:

Work done is the force applied on a body to move it through a particular distance.

   Work done  = force x distance

Now, let us find the distance;

    distance  = speed x time

    distance  = 3 x 7 = 21m

So;

    Work done  = 2 x 10¹ x 21  = 420J