Ammonia nh3 gas and oxygen o2 gas react to form nitrogen n2 gas and water h2o vapor. Suppose you have 2.0 mol of nh3 and 9.0 mol of o2 in a reactor. Calculate the largest amount of n2 that could be produced.

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Answer:

6 moles.

n(N2) = 2

n( NH3) 4.

where n( NH3)=2

So ,n( N2)= 1mole

Also , n(N2) =2

n( O2). 3

where n( O2) =9

so n(N2)= 6 moles

the largest amount of N2 produced is 6 moles.

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