Respuesta :
Slope-intercept form of an equation is y = mx + b, where m is the slope and b is the y-intercept.
To put this equation in the form of y = mx + b, we have to isolate the y. Here's how:
[tex]4x + 2y=24 \\ (4x + 2y)-4x=(24)-4x \\ 2y=-4x+24 \\ (2y)/2=(-4x+24)/2 \\ y= \frac{-4}{2}x + \frac{24}{2} \\ y=-2x+12[/tex]
In slope-intercept form, the equation is y = -2x + 12.
Hope this helps!
To put this equation in the form of y = mx + b, we have to isolate the y. Here's how:
[tex]4x + 2y=24 \\ (4x + 2y)-4x=(24)-4x \\ 2y=-4x+24 \\ (2y)/2=(-4x+24)/2 \\ y= \frac{-4}{2}x + \frac{24}{2} \\ y=-2x+12[/tex]
In slope-intercept form, the equation is y = -2x + 12.
Hope this helps!
The slope intercept form of the linear equation is y = -2x + 12
The slope intercept form of an equation is represented as follows:
y = mx + c
where
m = slope
c = y-intercept
Therefore,
4x + 2y = 24
2y = -4x + 24
divide both sides by 2
2y / 2 = -4x /2 + 24 / 2
y = -2x + 12
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