Question

A car leaves the pit after a refueling stop and accelerates uniformly to a speed of 62.2 m/s in 5.0 s to rejoin the race.

What is the car's acceleration during this time?

Answer 1

Answer:

The car's acceleration is: a = 12.44 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

$v_{f} = v_{o}+a*t$

where:

Vf = final velocity = 62.2 [m/s]

Vo = initial velocity = 0 (because the car stars from the rest)

a = acceleration [m/s²]

t = time = 5 [s]

62.2 = 0 + a*5

a = 12.44 [m/s²]