Answer:
Dy = 111.66 [m]
t = 3.5 [s]
Explanation:
To solve this problem we must use the equations of kinematics.
[tex]v_{f} = v_{o} - (g*t)\\[/tex]
where:
Vf = final velocity [m/s]
Vo = initial velocity = 27 [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time = 3.5 [s]
Note: The negative sign of the equation means that the gravity acceleration goes in opposite direction
Vf = 27 - (9,81*3,5)
Vf = - 7.33 [m/s] (this negative sign indicates that at this moment the snowball is going downwards)
To find how high the snowball was we must use the following equation:
[tex]Dy=v_{o} *t+\frac{1}{2}*g*t[/tex]
Dy = (27*3.5) + (0.5*9.81*3.5)
Dy = 94.5 + (17.16)
Dy = 111.66 [m]
The snow ball will achieve the height of 34.75 m and at that height, it will move with a speed of 61.3 m/s.
Given data:
The initial speed of the snow ball is, u = 27 m/s.
The time taken by the snow ball to achieve a height is, t = 3.5 s.
Clearly, the ball rising high will need a mathematical formula which utilizes the initial velocity and final velocity (v). So, using the first kinematic equation of motion as,
v = u + gt
Here,
g is the gravitational acceleration.
Solving as,
v = 27 + (9.8 × 3.5)
v = 61.3 m/s
Now, if we calculate the height achieved through the second kinetic equation of motion as,
[tex]h = ut + \dfrac{1}{2}(-g)t^{2}\\\\h = (27 \times 3.5) + \dfrac{1}{2} \times (-9.8) \times 3.5^{2}\\\\h = 34.75 \;\rm m[/tex]
Thus, we can conclude that the snow ball will achieve the height of 34.75 m and at that height, it will move with a speed of 61.3 m/s.
Learn more about the kinematic equations of motion here:
https://brainly.com/question/14355103
