Question

m2+12=48 solve the quadratic equations using any of the methods​

Answer 1

Answer:

Ok:

Step-by-step explanation:

So, you would have:

$m^2+12=48$

or

$m^2+12-48=0$

or

$m^2-36=0$

You know that $a^2-b^2 = (a+b)(a-b)$

so you get the factorized form of

$(m+6)(m-6)=0$.

Giving us two solutions of m=6 or -6.