Question

Consider the following chemical reaction.
CaF2(s) + H2SO4(aq) → CaSO4(s) + 2 HF(g)
When a certain amount of calcium fluoride (CaF2) reacts with sulfuric acid (H2SO4) in excess, the theoretical yield of hydrogen fluoride (HF) is 3.12 g. If the percent yield is 75.1%, what is the actual yield of HF in grams?

Answer 1

Explanation:

Actual yeild is equal 75.1% of the theoretical yeild

(75.1/100)×3.12

= 2.34312

approximately = 2.34 g.