Answer:
2.04 x 10⁻¹⁹J
Explanation:
Given parameters:
Frequency = 3.08 x 10¹⁴Hz
Unknown:
The energy of the photon = ?
Solution:
The energy of a photon is given as;
E = hf
Where h is the planck's constant
f is the frequency
Insert the parameters and solve;
E = 6.63 x 10⁻³⁴ x 3.08 x 10¹⁴
E = 20.4 x 10⁻³⁴⁺¹⁴
E = 20.4 x 10⁻²⁰ = 2.04 x 10⁻¹⁹J
