Question

Calculate the number of grams of CuSO4 found in 3.29 mL of a 4.00 M CuSO4 solution. ______ grams CuSO4

Answer 1

Answer:

0.0132 g CuSO₄

General Formulas and Concepts:

$\text{Molarity}=\frac{\text{moles of solute}}{\text{liters of solution}}$

Explanation:

Step 1: Define variables

3.29 mL

4.00 M CuSO₄

x g CuSO₄

Step 2: Define conversions

1000 mL = 1 L

Step 3: Solve

1. Convert mL to L:                         $\text{3.29 mL}(\frac{\text{1 L}}{\text{1000 mL}} )$ = 0.00329 L
2. Substitute:                                   $\text{4.00 M} \ CuSO_4=\frac{\text{x g} \ CuSO_4}{\text{0.00329 L}}$
3. Multiply both sides by L:            $\text{0.01316} \ CuSO_4=\text{x g} \ CuSO_4$
4. Rewrite:                                       $x = 0.01316 \ g \ CuSO_4$

Step 4: Simplify

We are given 3 sig figs.

0.01316 g CuSO₄ ≈ 0.0132 g CuSO₄