Answer:
Step-by-step explanation:
Answer Text
an equilateral triangle
a right angled triangle
an isosceles triangle
None of these
Answer :
A
Solution :
Acute angle between the lines x2+4xy+y2=0 is tan2(24−1−−−−√)/(1+1)=tan−13–√=tan−1π/3. Angle bisectors of x2+4xy+y2=0 are given by x2−y21−1=xy2
x2−y2=0⇒x=±y
As x+y=0 is perpendicular to x−y=4, so the given triangle is equilateral triangle
