Anyone ??? Help with this one

Answer:
(4x-3y)(4x+3y)
Step-by-step explanation:
This is a difference of squares equation. As it says, ([tex]x^{2} -y^2[/tex]) is equal to (x-y)(x+y)
Simply apply the formula to your numbers, [tex]16x^{2} -9y^2[/tex].
It gives the hint of [tex]16x^{2}[/tex] is equal to (4x)^2. and, 9y^2 is equal to (3y)^2, since if you square 4x and 9y, they get 16x^2 and 9y^2 respectively.
Now, you need to do (4x-3y)(4x+3y)
Hope this helps