Question

The probability that an employee at a company uses illegal drugs is 0.08. The probability that an employee is male is 0.62. Assuming that these events are independent, what is the probability that a randomly chosen employee is a male drug user?

Answer 1

Answer: 0.0496

Step-by-step explanation:

If events are said to be independent it means that the probability of one happening does not affect the probability of the other.

In calculating the probability that an employee is both male and a drug user using independent events, multiply the probabilities of the individual events to find the probability of the the events happening together.

P(A) * P(B) = P(A and B)

0.08 * 0.62 = 0.0496

Answer 2

Probabilities are used to determine the chances of events.

The probability that a randomly chosen employee is a male drug user is 0.0496

Represent the two events as A and B, such that:

$P(A) = 0.08$

$P(B) =0.62$

So, the probability that a randomly chosen employee is a male drug user is calculated as:

$P(A\ and\ B) =P(A) \times P(B)$

This gives

$P(A\ and\ B) =0.08 \times 0.62$

Multiply

$P(A\ and\ B) =0.0496$

Hence, the probability that a randomly chosen employee is a male drug user is 0.0496

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