Answer:
28 seconds.
Explanation:
Apply the first equation of motion as;
v=u +at where;
v= final velocity of the plane = 70m/s
u=initial velocity of the plane= 0m/s -----it was at rest
a= acceleration uniform =2.5 m/s²
t= time required for takeoff = ?
Substitute values in the equation as;
v= u + at
70 = 0 + 2.5*t
70 = 2.5t
70/2.5 = 2.5/2.5t
28 = t
Time required for takeoff is 28 seconds.
