Question

two separate bulbs contain ideal gases A and B the density of A is twice as that of gas B if two gases are at same temperature the ration of the pressure of A to that of B is​

Answer 1

To find density :-
PM=DRT
∴D=
RT
PM
​


Given :-
D
1
​
=2D
2
​
∣ M
1
​
=
2
1
​
M
2
​
∣ T
1
​
=T
2
​


D
2
​

D
1
​

​
=2 ∣
M
2
​

M
1
​

​
=
2
1
​


Now D=PM (∵R&T are constant)

D
2
​

D
1
​

​
=
P
2
​
M
2
​

P
1
​
M
1
​

​


2=
P
2
​

P
1
​

​
×
2
1
​


2×2=
P
2
​

P
1
​

​


∴
P
2
​

P
1
​

​
=4

Ans is C) 4