Question

2 point
Question 9
An object is shot from the ground at 75m/s at an angle of 45° above the horizontal. How high does the object get before beginning its descent?

Answer 1

Answer:

Before beginning its descent, the object gets 143.5 meters high

Explanation:

Projectile Motion

It's known as the type of motion that experiences an object that is projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and $g=9.8m/s^2$ the acceleration of gravity, then the maximum height reached by the object is:

$\displaystyle y_m=\frac{v_o^2\sin^2\theta}{2g}$

The object is shot at vo=75 m/s at an angle of θ=45°. The maximum height is calculated below:

$\displaystyle y_m=\frac{75^2\sin^2 45^\circ}{2\cdot 9.8}$

$\displaystyle y_m=\frac{5625\cdot 0.707^2}{19.6}$

$y_m=143.5\ m$

Before beginning its descent, the object gets 143.5 meters high