Answer:
The ball will travel 4.45 m horizontally before hitting the ground
Explanation:
Horizontal Motion
When an object is launched horizontally with a speed v from a height h, the maximum horizontal distance traveled by the object, also called range can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
The question provides us with the following data:
Initial speed of the ball: vo=9 m/s
Height: h=1.2
Proceed to calculate the range:
[tex]\displaystyle d=9\ m/s\cdot\sqrt{\frac {2\cdot 1.2\ m}{9.8\ m/s^2}}[/tex]
Calculating:
[tex]\displaystyle d=9\ m/s\cdot\sqrt{0.2449\ s^2}[/tex]
[tex]d=9\ m/s\cdot 0.4949\ s[/tex]
d=4.45 m
The ball will travel 4.45 m horizontally before hitting the ground