For the function f ( x ) = − 2x^2 + 2x + 8 , evaluate and fully simplify each of the following.

f ( x + h ) =

f ( x + h ) − f ( x ) =

Respuesta :

Answer:

[tex]f(x+h)=- 2x^2-4xh-2h^2 + 2x+2h + 8[/tex]

[tex]f ( x + h ) - f ( x )= h(-4x-2h+2)[/tex]

Step-by-step explanation:

Given the function:

[tex]f ( x ) = - 2x^2 + 2x + 8[/tex]

Find

  • f ( x + h )
  • f ( x + h ) - f ( x )

Recall the identity to square a binomial:

[tex](a+b)^2=a^2+2ab+b^2[/tex]

[tex]f(x+h)=- 2(x+h)^2 + 2(x+h) + 8[/tex]

Squaring the binomial:

[tex]f(x+h)=- 2(x^2+2xh+h^2) + 2(x+h) + 8[/tex]

Multiplying:

[tex]\boxed{f(x+h)=- 2x^2-4xh-2h^2 + 2x+2h + 8}[/tex]

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To compute f ( x + h ) - f ( x ), we use the last result:

[tex]f ( x + h ) - f ( x )=- 2x^2-4xh-2h^2 + 2x+2h + 8-(- 2x^2 + 2x + 8)[/tex]

Multiplying:

[tex]f ( x + h ) - f ( x )=- 2x^2-4xh-2h^2 + 2x+2h + 8+ 2x^2 - 2x - 8[/tex]

Simplifying similar terms:

[tex]f ( x + h ) - f ( x )= -4xh-2h^2+2h[/tex]

Factoring:

[tex]\boxed{f ( x + h ) - f ( x )= h(-4x-2h+2)}[/tex]

Note: This expression is commonly used to compute the first derivative of a function by its definition.

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