Answer:
[tex]f(x+h)=- 2x^2-4xh-2h^2 + 2x+2h + 8[/tex]
[tex]f ( x + h ) - f ( x )= h(-4x-2h+2)[/tex]
Step-by-step explanation:
Given the function:
[tex]f ( x ) = - 2x^2 + 2x + 8[/tex]
Find
Recall the identity to square a binomial:
[tex](a+b)^2=a^2+2ab+b^2[/tex]
[tex]f(x+h)=- 2(x+h)^2 + 2(x+h) + 8[/tex]
Squaring the binomial:
[tex]f(x+h)=- 2(x^2+2xh+h^2) + 2(x+h) + 8[/tex]
Multiplying:
[tex]\boxed{f(x+h)=- 2x^2-4xh-2h^2 + 2x+2h + 8}[/tex]
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To compute f ( x + h ) - f ( x ), we use the last result:
[tex]f ( x + h ) - f ( x )=- 2x^2-4xh-2h^2 + 2x+2h + 8-(- 2x^2 + 2x + 8)[/tex]
Multiplying:
[tex]f ( x + h ) - f ( x )=- 2x^2-4xh-2h^2 + 2x+2h + 8+ 2x^2 - 2x - 8[/tex]
Simplifying similar terms:
[tex]f ( x + h ) - f ( x )= -4xh-2h^2+2h[/tex]
Factoring:
[tex]\boxed{f ( x + h ) - f ( x )= h(-4x-2h+2)}[/tex]
Note: This expression is commonly used to compute the first derivative of a function by its definition.